1+1=3

#1
a=b
ab=b^2
ab-a^2=b^2-a^2
a(b-a)=(b-a)(b+a)
a=(a+b)
a=2a

a=2a, and a=1 then 1=2. If 1=2 then 1+1=3

As you can see, 1+1=3.
 
#3
but if b=1 and a = anything but 1, you can't say a=b.

LOL, Kazzy backed out.

and serbs, I was already on my second year of algebra when I was your age. I'm taking calc this year, I know algebra.
 

Kazmarov

For a Free Scotland
#6
Let x=y. Then

x - y + y = y

x - y + y y
--------- = ---
x-y x-y

y y
1 + --- = ---
x-y x-y

1 = 0
If p then q, q can equal anything if p is false. This is bullshit math.
 
#7
1=1 as well, as stated in the first statement of a=b. So 1=1 and 2. 1 can equal 3 if I want to, and since 3 is a better number than 4, I choose three.
 
#8
you never defined which instance of 1 u were using in each occurance of it in that statement. therfore my conclusion is also correct, and my insult holds.
 

Kazmarov

For a Free Scotland
#9
Step four: you obtain the result in step five by dividing (b-a). If a=b, then that equals zero, and the equation is undefined.

Q.E.D, bitch.